12x^2y^2+28xy+15=

Solution for 12x^2y^2+28xy+15= equation:

Simplifying
12x2y2 + 28xy + 15 = 0

Reorder the terms:
15 + 28xy + 12x2y2 = 0

Solving
15 + 28xy + 12x2y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(3 + 2xy)(5 + 6xy) = 0

Subproblem 1
Set the factor '(3 + 2xy)' equal to zero and attempt to solve:

Simplifying
3 + 2xy = 0

Solving
3 + 2xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2xy = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2xy = 0 + -3
2xy = 0 + -3

Combine like terms: 0 + -3 = -3
2xy = -3

Divide each side by '2y'.
x = -1.5y-1

Simplifying
x = -1.5y-1
Subproblem 2
Set the factor '(5 + 6xy)' equal to zero and attempt to solve:

Simplifying
5 + 6xy = 0

Solving
5 + 6xy = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 6xy = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 6xy = 0 + -5
6xy = 0 + -5

Combine like terms: 0 + -5 = -5
6xy = -5

Divide each side by '6y'.
x = -0.8333333333y-1

Simplifying
x = -0.8333333333y-1
Solution
x = {-1.5y-1, -0.8333333333y-1}